Time, Speed, Distance - Early Departure

CAT 1991 Slot 1 · QA · Hard · Arithmetic

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Every day Neera's husband meets her at the city railway station at 6.00 p.m. and drives her to their residence. One day she left early from the office and reached the railway station at 5.00 p.m. She started walking towards her home, met her husband coming from their residence on the way and they reached home 10 minutes earlier than the usual time. For how long did she walk?

  1. A.

    1 hour

  2. B.

    50 minutes

  3. C.

    ½ hour

  4. D.

    55 minutes

Answer

D

Explanation

Since they reached home 10 minutes earlier than usual, the husband saved 10 minutes of total driving time (round trip from the meeting point to the station and back). This means he saved 5 minutes on the journey to the station. So he reached the meeting point 5 minutes earlier than his usual 6:00 p.m. arrival, i.e., at 5:55 p.m. Neera reached the station at 5:00 p.m. and walked until she met him at 5:55 p.m. Therefore, she walked for 5:55−5:00=555:55 - 5:00 = 55 minutes.

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