Student Course Grades and GPA Analysis

GPA of Preeti = 3.2 \implies rac{F + D + x + D + y}{5} = 3.2 \implies 0 + 2 + x + 2 + y = 16 \implies x + y = 12. The only possible combination for $x$ and $y$ (grades out of maximum 6 points) is $6 + 6$, corresponding to grade A in Statistics and Operations. Hence, Preeti obtained grade A in Statistics.

Tara's total points $= 2.4 imes 5 = 12$. She scored the same grade in three subjects. Let her grades be $3x + y + z = 12$.

• She cannot have 3 A's (sum exceeds 12).
• If she scores 3 B's, total $= 12$, so remaining two must be F's ($3 imes 4 + 0 + 0 = 12$).
• If she scores 3 C's or 3 D's, it leads to a contradiction in available grades. Thus, her grades are three B's and two F's. Since Marketing is B, Operations could be B (same as Manab) or F.

Gowri's GPA $= 3.8 \implies 3 + 3 + 6 + x + 4 = 19 \implies x = 3$, which is grade C. Rahul's grade in Strategy $= (4.2 imes 5) - (6 + 3 + 6 + 0) = 6 \implies A$. Fazal's grade in Strategy $= (2.4 imes 5) - (2 + 0 + 4 + 2) = 4 \implies B$. For Hari, Strategy grade is higher than C. Thus, Gowri's grade (C, point 3) was higher than Hari's (which is D, point 2).

Fazal's GPA $= 2.4 \implies 2 + 0 + 4 + x + 2 = 12 \implies x = 4$ (Grade B in Strategy). Utkarsh's grade in Marketing is equal to Fazal's in Strategy $\implies$ B (4 points). Utkarsh's GPA $= 3.0 \implies Y + 4 + 0 + 3 + 6 = 15 \implies Y = 2$ (Grade D in Finance).