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Olympic Bidding Voting Analysis

CAT 2005 Slot 1 · Data Interpretation & Logical Reasoning · Hard · DILR

This is a hard Data Interpretation & Logical Reasoning question set from the CAT 2005 Slot 1 paper. It tests DILR. The full answer key and a step-by-step explanation are below — try it yourself first, then reveal the solution.

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Passage / data set

Four cities: Beijing (B), London (L), New York (NY), Paris (P). Round 1: London (30), NY (12 - eliminated), Total = 82. Round 2: Paris (32), Beijing (21 - eliminated), Total = 83. Round 3: Total = 75, difference between two final cities is 1.

Rules:

  • Representative cannot vote if their city is in contention.
  • A member can vote for at most 2 distinct cities across all rounds.
  • All voters for L and P in Round 1 continued voting for them in Round 2.
  • 75% of Round 1 B voters voted for B in Round 2.
  • NY voters in Round 1 voted for B or P in Round 2.
  • 50% of Round 1 B voters voted for P in Round 3.

Question 1 of 4

What percentage of members from among those who voted for New York in round 1, voted for Beijing in round 2?

  1. A.

    33.33

  2. B.

    50

  3. C.

    66.67

  4. D.

    75

Answer

D

Explanation

Round 1 total =82= 82. L(30) + P(24) + B(16) + NY(12) = 82. In Round 2, B got 21 votes. 75% of B's Round 1 voters =12= 12. Remaining votes for B in Round 2 =21−12=9= 21 - 12 = 9. These 9 votes came from NY voters. Percentage =912×100%=75%= \frac{9}{12} \times 100\% = 75\%.

Question 2 of 4

What is the number of votes cast for Paris in round 1?

  1. A.

    16

  2. B.

    18

  3. C.

    22

  4. D.

    24

Answer

D

Explanation

Round 1 total votes =82= 82. London =30= 30, New York =12= 12, Beijing =16= 16. Paris =82−(30+12+16)=24= 82 - (30 + 12 + 16) = 24.

Question 3 of 4

What percentage of members from among those who voted for Beijing in round 2 and were eligible to vote in round 3, voted for London?

  1. A.

    33.33

  2. B.

    38.10

  3. C.

    50

  4. D.

    66.67

Answer

D

Explanation

21 members voted for Beijing in Round 2. 9 of them (from NY in R1) became ineligible in R3. Remaining eligible =21−9=12= 21 - 9 = 12. Out of 16 original B voters, 50% (8 members) voted for Paris in R3. 4 of them voted for P in R2, and 4 in R3. So 8 eligible voted for London in R3. Percentage =812×100%=66.67%= \frac{8}{12} \times 100\% = 66.67\%.

Question 4 of 4

Which of the following statements must be true? I. IOC member from New York must have voted for Paris in round 2. II. IOC member from Beijing voted for London in round 3.

  1. A.

    Only I

  2. B.

    Only II

  3. C.

    Both I and II

  4. D.

    Neither I nor II

Answer

A

Explanation

NY member couldn't vote in R1 (NY in contention). In R2, NY was eliminated, so NY member voted for Paris. Thus Statement I is definitely true.

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