Funky Pizzeria

CAT 2017 Slot 2 · DILR · Medium · Data Interpretation

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Passage / data set

Funky Pizzeria was required to supply Pizzas to three different parties. The total number of Pizzas it had to deliver was 800. 70% of which was to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.

Pizzas could be of Thin Crust (T) or Deep Dish (D) variety and come in either Normal Cheese (NC) or Extra Cheese (EC) versions. Hence, there are 4 types of Pizzas: T – NC, T – EC, D-NC, D-EC. Partial information about proportions of T and NC pizzas ordered by the three parties are given below.

Thin Crust(T)Normal Cheese(NC)
Party 10.6
Party 20.550.3
Party 30.65
Total0.3750.52

Question 1 of 4

How many Thin Crust pizzas were to be delivered to Party 3?

  1. A.

    398

  2. B.

    162

  3. C.

    196

  4. D.

    364

Answer

B

Explanation

Total pizzas = 800. Party 3 receives 70% of 800 = 560 pizzas. Party 1 and Party 2 each receive 15% of 800 = 120 pizzas. Total Thin Crust pizzas = 0.375×800=3000.375 \times 800 = 300. Thin Crust for Party 1 = 0.6×120=720.6 \times 120 = 72. Thin Crust for Party 2 = 0.55×120=660.55 \times 120 = 66. Thin Crust for Party 3 = 300−(72+66)=162300 - (72 + 66) = 162.

Question 2 of 4

How many Normal Cheese pizzas were required to be delivered to Party 1?

  1. A.

    104

  2. B.

    84

  3. C.

    16

  4. D.

    196

Answer

C

Explanation

Total Normal Cheese pizzas = 0.52×800=4160.52 \times 800 = 416. NC for Party 2 = 0.3×120=360.3 \times 120 = 36. NC for Party 3 = 0.65×560=3640.65 \times 560 = 364. NC for Party 1 = 416−(36+364)=16416 - (36 + 364) = 16.

Question 3 of 4

For Party 2, if 50% of the Normal Cheese pizzas were of Thin Crust variety, what was the difference between the numbers of TEC and D-EC pizzas to be delivered to Party 2?

  1. A.

    18

  2. B.

    12

  3. C.

    30

  4. D.

    24

Answer

B

Explanation

Party 2 total pizzas = 120. Normal Cheese (NC) = 36. Thin Crust (T) = 66. Since 50% of NC pizzas are T (i.e. T-NC) = 0.5×36=180.5 \times 36 = 18. So, T-EC = 66−18=4866 - 18 = 48. D-NC = 36−18=1836 - 18 = 18. D-EC = 120−(T−NC+T−EC+D−NC)=120−(18+48+18)=36120 - (T-NC + T-EC + D-NC) = 120 - (18 + 48 + 18) = 36. Difference between T-EC and D-EC = 48−36=1248 - 36 = 12.

Question 4 of 4

Suppose that a T-NC pizza cost as much as a D-NC pizza, but 3/5th of the price of a D-EC pizza. A D-EC pizza costs Rs. 50 more than a T-EC pizza, and the latter costs Rs. 500. If 25% of the Normal Cheese pizzas delivered to Party 1 were of Deep Dish variety, what was the total bill for Party 1?

  1. A.

    Rs. 59480

  2. B.

    Rs. 59840

  3. C.

    Rs. 42520

  4. D.

    Rs. 45240

Answer

A

Explanation

Price of T-EC = Rs. 500. Price of D-EC = 500+50=Rs. 550500 + 50 = \text{Rs. } 550. Price of T-NC = Price of D-NC = 35×550=Rs. 330\frac{3}{5} \times 550 = \text{Rs. } 330.

For Party 1: Total pizzas = 120, NC = 16, T = 72. 25% of NC are D (D-NC) = 0.25×16=40.25 \times 16 = 4. T-NC = 16−4=1216 - 4 = 12. T-EC = 72−12=6072 - 12 = 60. D-EC = 120−(12+60+4)=44120 - (12 + 60 + 4) = 44.

Total Bill = (12×330)+(4×330)+(60×500)+(44×550)=5280+30000+24200=Rs. 59480(12 \times 330) + (4 \times 330) + (60 \times 500) + (44 \times 550) = 5280 + 30000 + 24200 = \text{Rs. } 59480.

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