Number of Real Roots of Trigonometric Exponential Equation

CAT 2019 Slot 1 · Quantitative Ability · Easy · Trigonometry

This is an easy Quantitative Ability question from the CAT 2019 Slot 1 paper. It tests Trigonometry. The full answer key and a step-by-step explanation are below — try it yourself first, then reveal the solution.

The number of the real roots of the equation 2cos(x(x+1))=2x+2x2\cos(x(x + 1)) = 2^x + 2^{-x} is

  1. A.

    0

  2. B.

    Infinite

  3. C.

    1

  4. D.

    2

Answer

C

Explanation

By AM-GM inequality, 2x+2x22x2x=22^x + 2^{-x} \ge 2\sqrt{2^x \cdot 2^{-x}} = 2. Also, 2cos(x(x+1))22\cos(x(x+1)) \le 2. Equality holds if and only if both sides equal 2. RHS =2    2x=1    x=0= 2 \implies 2^x = 1 \implies x = 0. Checking LHS for x=0x = 0: 2cos(0)=22\cos(0) = 2, which satisfies the equation. So x=0x = 0 is the only real root.

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