Infinite Equilateral Triangles Area Sum

CAT 2019 Slot 1 · QA · Easy · Geometry

Given an equilateral triangle T1T_1 with side 24 cm, a second triangle T2T_2 is formed by joining the midpoints of the sides of T1T_1. Then a third triangle T3T_3 is formed by joining the midpoints of the sides of T2T_2. If this process of forming triangles is continued, the sum of the areas, in sq cm, of infinitely many such triangles T1,T2,T3,T_1, T_2, T_3, \dots will be

  1. A.

    1923192\sqrt{3}

  2. B.

    1643164\sqrt{3}

  3. C.

    2483248\sqrt{3}

  4. D.

    1883188\sqrt{3}

Answer

A

Explanation

Area of T1=34×242=1443T_1 = \frac{\sqrt{3}}{4} \times 24^2 = 144\sqrt{3}. Joining midpoints reduces area by a factor of 14\frac{1}{4}. So areas form an infinite GP with a=1443a = 144\sqrt{3} and r=14r = \frac{1}{4}. Sum = a1r=144311/4=14433/4=1923\frac{a}{1 - r} = \frac{144\sqrt{3}}{1 - 1/4} = \frac{144\sqrt{3}}{3/4} = 192\sqrt{3}.

Practise this under exam conditions

Sign in to solve it with a live timer, the on-screen CAT calculator, and streak and accuracy tracking across every question you attempt.

Solve in the workspace