Length of Chord in Circle

Set $O$ as the origin $(0,0)$. $A = (0, 4)$ and $B = (3, 0)$. The line passing through $A$ and $B$ has equation $\frac{x}{3} + \frac{y}{4} = 1 \implies 4x + 3y - 12 = 0$. The perpendicular distance $d$ from $O(0,0)$ to line $AB$ is: $d = \frac{|12|}{\sqrt{4^2 + 3^2}} = \frac{12}{5} = 2.4\text{ meters}$ The length of chord $PQ$ in a circle of radius $R = 5$ with distance $d = 2.4$ from the center is: $PQ = 2\sqrt{R^2 - d^2} = 2\sqrt{5^2 - 2.4^2} = 2\sqrt{25 - 5.76} = 2\sqrt{19.24} \approx 2 \times 4.386 = 8.77\text{ m} \approx 8.8\text{ m}$