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Examination marks calculation

CAT 2020 Slot 3 · Quantitative Ability · Easy · Percentages

This is an easy Quantitative Ability question from the CAT 2020 Slot 3 paper. It tests Percentages. The full answer key and a step-by-step explanation are below — try it yourself first, then reveal the solution.

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In the final examination, Bishnu scored 52% and Asha scored 64%. The marks obtained by Bishnu is 23 less, and that by Asha is 34 more than the marks obtained by Ramesh. The marks obtained by Geeta, who scored 84%, is

  1. A.

    399

  2. B.

    439

  3. C.

    357

  4. D.

    417

Answer

A

Explanation

Let total maximum marks be MM. Bishnu's marks = 0.52M=R−230.52 M = R - 23 Asha's marks = 0.64M=R+340.64 M = R + 34

Subtracting the two equations: 0.64M−0.52M=57  ⟹  0.12M=57  ⟹  M=570.12=4750.64 M - 0.52 M = 57 \implies 0.12 M = 57 \implies M = \frac{57}{0.12} = 475.

Geeta's marks = 84%84\% of 475=0.84×475=399475 = 0.84 \times 475 = 399.

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