Range of Algebraic Expression

CAT 2022 Slot 3 · QA · Medium · Algebra

If c=16xy+49yxc = \frac{16x}{y} + \frac{49y}{x} for some non-zero real numbers xx and yy, then cc cannot take the value

  1. A.

    -70

  2. B.

    60

  3. C.

    -50

  4. D.

    -60

Answer

C

Explanation

Let k=xyk = \frac{x}{y}. Then c=16k+49kc = 16k + \frac{49}{k}.

  • If k>0k > 0, by AM-GM: c216k49k=2×4×7=56c \ge 2\sqrt{16k \cdot \frac{49}{k}} = 2 \times 4 \times 7 = 56
  • If k<0k < 0, let k=tk = -t (t>0t > 0): c=(16t+49t)56c = -\left(16t + \frac{49}{t}\right) \le -56

Thus, cc can take any value in (,56][56,)(-\infty, -56] \cup [56, \infty). Therefore, cc cannot take any value in the interval (56,56)(-56, 56).

Among the options:

  • 7056-70 \le -56 (valid)
  • 605660 \ge 56 (valid)
  • 6056-60 \le -56 (valid)
  • 50-50 lies in (56,56)(-56, 56) (invalid)

Hence, cc cannot take the value 50-50.

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