Incircle Radius of Right Triangle in Rectangle

CAT 2024 Slot 1 · QA · Easy · Geometry

ABCD is a rectangle with sides AB = 56 cm and BC = 45 cm, and E is the midpoint of side CD. Then, the length, in cm, of radius of incircle of ADE\triangle ADE is

Answer

10

Explanation

In rectangle ABCDABCD, AD=BC=45AD = BC = 45 cm, and CD=AB=56CD = AB = 56 cm. Since EE is the midpoint of CDCD, DE=28DE = 28 cm. ADE\triangle ADE is right-angled at DD.

Hypotenuse AE=452+282=2025+784=2809=53AE = \sqrt{45^2 + 28^2} = \sqrt{2025 + 784} = \sqrt{2809} = 53 cm.

Inradius rr of right-angled triangle with legs a,ba, b and hypotenuse cc: r=a+bc2=45+28532=202=10 cmr = \frac{a + b - c}{2} = \frac{45 + 28 - 53}{2} = \frac{20}{2} = 10\text{ cm}

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