Modulus equation solution

Case 1: $2a - 3 \ge 0 \implies a \ge 1.5$. $2a - 3 = 3a + 2 \implies a = -5$ (Invalid since $-5 < 1.5$).

Case 2: $2a - 3 < 0 \implies a < 1.5$. $-(2a - 3) = 3a + 2 \implies -2a + 3 = 3a + 2 \implies 5a = 1 \implies a = 1/5$. Since $1/5 < 1.5$, $a = 1/5$ is valid.