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Passing marks and percentage

CMAT 2018 · Quantitative Techniques & Data Interpretation · Easy · Percentages

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A student who gets 20% marks fails by 20 marks, but another student who gets 36% marks gets 44 marks more than minimum passing marks. Find the maximum number of marks and percentage necessary for passing.

  1. A.

    300, 20%

  2. B.

    600, 20%

  3. C.

    400, 25%

  4. D.

    400, 20%

Answer

C

Explanation

Let maximum marks be MM. Passing marks = 0.20M+20=0.36M−440.20M + 20 = 0.36M - 44. 0.16M=64  ⟹  M=400.0.16M = 64 \implies M = 400. Passing marks = 0.20(400)+20=1000.20(400) + 20 = 100. Passing percentage = 100400×100=25%\frac{100}{400} \times 100 = 25\%.

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