Dishonest trader false weight

CMAT 2018 · Quantitative Techniques & Data Interpretation · Easy · Profit and Loss

A shopkeeper sells rice at the cost price, but uses false weight. He gains 20% in this process. What weight does he use for one kilogram?

  1. A.

    73313733\frac{1}{3} g

  2. B.

    750 g

  3. C.

    83313833\frac{1}{3} g

  4. D.

    850 g

Answer

C

Explanation

Let xx be the false weight used for 1000 g. Gain%=1000−xx×100\text{Gain\%} = \frac{1000 - x}{x} \times 100 20=1000−xx×100  ⟹  0.20x=1000−x  ⟹  1.2x=100020 = \frac{1000 - x}{x} \times 100 \implies 0.20 x = 1000 - x \implies 1.2 x = 1000 x=833.33 g=83313 g.x = 833.33\text{ g} = 833\frac{1}{3}\text{ g.}

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