Question

There are three boxes of three different colours- Green, Blue and Red, and 6 toys of which 2 are of Green colour, 2 are of Blue colour and 2 are of Red colour. The toys are packed in the three boxes such that each box has 2 toys of different colours in it and also the colour of the box is different from the colour of the toys packed in it. Now, 10 chocolates are kept in these boxes in such a way that the Green box has the maximum possible chocolates in it whereas, the Red box has the least possible chocolates in it. Each box should have at least one chocolate and no two boxes have the same number of chocolates.

Which of the following is true?

Accepted Answer

D. Box contents based on constraints: - Green box cannot have green toys, so it has Blue and Red toys. - Blue box cannot have blue toys, so it has Green and Red toys. - Red box cannot have red toys, so it has Green and Blue toys. Chocolates distribution (total 10): - Red box has least $\ge 1$. - Green box has max. - Distinct values: Red = 1, Blue = 2, Green = 7. - The box with Green and Red toys is the Blue box, which has 2 chocolates.

Boxes, Toys and Chocolates

Explanation

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