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Sector-wise Distribution of Workforce of India

CMAT 2022 · Quantitative Techniques & Data Interpretation · Medium · Data Interpretation

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Passage / data set

Consider the following table that shows the percentage (%) distribution of workforce of India and ratio of male to female workforce of India in different employment sectors during a given year. Total workforce in all the sectors put together is 60 lakhs.

Employment SectorPercentage (%) DistributionRatio of Male to Female (M : F)
Service (SE)15%3:2
Sales (SA)12%5:3
Construction and Maintenance (CM)9%5:4
Professional (PR)18%5:7
Management (MA)21%3:4
Production and Transport (PT)19%5:3
Others (OT)6%3:5
Sector-wise Distribution of Workforce of India

Question 1 of 3

The number of male workforce in SA and MA sectors put together is approximately what percent of the total number of workforce in PT sector?

  1. A.

    82%

  2. B.

    87%

  3. C.

    89%

  4. D.

    85%

Answer

B

Explanation

Total workforce = 60 lakhs.

  • SA: total =12%×60=7.2= 12\% \times 60 = 7.2 lakhs. Male in SA =58×7.2=4.5= \frac{5}{8} \times 7.2 = 4.5 lakhs (450 thousand).
  • MA: total =21%×60=12.6= 21\% \times 60 = 12.6 lakhs. Male in MA =37×12.6=5.4= \frac{3}{7} \times 12.6 = 5.4 lakhs (540 thousand). Total male in SA & MA =450+540=990= 450 + 540 = 990 thousand. Total workforce in PT =19%×60=11.4= 19\% \times 60 = 11.4 lakhs (1140 thousand). Percentage =9901140×100≈86.84%≈87%= \frac{990}{1140} \times 100 \approx 86.84\% \approx 87\%.

Question 2 of 3

The number of female workforce in SE and PR sectors put together is what percent of the number of male workforce in CM sector?

  1. A.

    330%

  2. B.

    318%

  3. C.

    320%

  4. D.

    80%

Answer

A

Explanation

  • SE female =25×(15%×60)=25×9=3.6= \frac{2}{5} \times (15\% \times 60) = \frac{2}{5} \times 9 = 3.6 lakhs (360 thousand).
  • PR female =712×(18%×60)=712×10.8=6.3= \frac{7}{12} \times (18\% \times 60) = \frac{7}{12} \times 10.8 = 6.3 lakhs (630 thousand). Total female in SE & PR =360+630=990= 360 + 630 = 990 thousand.
  • CM male =59×(9%×60)=3= \frac{5}{9} \times (9\% \times 60) = 3 lakhs (300 thousand). Percentage =990300×100=330%= \frac{990}{300} \times 100 = 330\%.

Question 3 of 3

The difference in the number of female workforce in SA and MA sectors put together and the number of female workforce in PT sector is:

  1. A.

    5.1 lakhs

  2. B.

    7.5 lakhs

  3. C.

    5.6 lakhs

  4. D.

    13.2 lakhs

Answer

C

Explanation

  • SA female =38×7.2=2.7= \frac{3}{8} \times 7.2 = 2.7 lakhs.
  • MA female =47×12.6=7.2= \frac{4}{7} \times 12.6 = 7.2 lakhs. Total female in SA & MA =2.7+7.2=9.9= 2.7 + 7.2 = 9.9 lakhs.
  • PT female =38×(19%×60)=38×11.4=4.275= \frac{3}{8} \times (19\% \times 60) = \frac{3}{8} \times 11.4 = 4.275 lakhs. Difference =9.9−4.275=5.625≈5.6= 9.9 - 4.275 = 5.625 \approx 5.6 lakhs.

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