Question

Reema had 'n' chocolates. She distributed them among 4 children in the ratio of $\frac{1}{2} : \frac{1}{3} : \frac{1}{5} : \frac{1}{8}$. If she gave them each one a complete chocolate, the minimum number of chocolates she had distributed.

Accepted Answer

B. To clear fractions, find LCM of denominators $(2, 3, 5, 8) = 120$. Ratio becomes: $$120 	imes \frac{1}{2} : 120 	imes \frac{1}{3} : 120 	imes \frac{1}{5} : 120 	imes \frac{1}{8} = 60 : 40 : 24 : 15$$ Sum of ratio terms = $60 + 40 + 24 + 15 = 139$. Minimum number of chocolates distributed = $139$.

Ratio of Distribution of Chocolates

Explanation

Practise this under exam conditions