Question

Mr Ajay started from his house, walked 4 km north, then 6 km west, then 12 km south. How far was he from his home then?

Accepted Answer

D. Position relative to home: North-South displacement = $4 - 12 = -8$ km (8 km South). East-West displacement = $-6$ km (6 km West). Direct distance = $\sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10$ km.

Direction and Distance - Ajay's Walk

Explanation

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