Common Internal Tangent of Circles

XAT 2014 · Quantitative Ability & Data Interpretation · Medium · Geometry

There are two circles C1C_1 and C2C_2 of radii 3 and 8 units respectively. The common internal tangent, T, touches the circles at points P1P_1 and P2P_2 respectively. The line joining the centers of the circles intersects T at X. The distance of X from the center of the smaller circle is 5 units. What is the length of the line segment P1P2P_1P_2?

  1. A.

    ≤ 13

  2. B.

    13 and ≤ 14

  3. C.

    14 and ≤ 15

  4. D.

    15 and ≤ 16

  5. E.

    16

Answer

C

Explanation

In △OP1X\triangle OP_1X, P1X=52−32=4P_1X = \sqrt{5^2 - 3^2} = 4. By similar triangles △OP1X∼△O′P2X\triangle OP_1X \sim \triangle O'P_2X, XP2P1X=O′P2OP1=83  ⟹  XP2=4×83=10.66\frac{XP_2}{P_1X} = \frac{O'P_2}{OP_1} = \frac{8}{3} \implies XP_2 = 4 \times \frac{8}{3} = 10.66. P1P2=P1X+XP2=4+10.66=14.66P_1P_2 = P_1X + XP_2 = 4 + 10.66 = 14.66 units.

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