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Equation of Quadratic Graph

XAT 2015 · Quantitative Ability & Data Interpretation · Easy · Coordinate Geometry

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Find the equation of the parabola graph passing through (−3,−10)(-3, -10) and vertex near (0,−19)(0, -19).

  1. A.

    y=3x−4y = 3x - 4

  2. B.

    y=2x2−40y = 2x^2 - 40

  3. C.

    x=2y2−40x = 2y^2 - 40

  4. D.

    y=2x2+3x−19y = 2x^2 + 3x - 19

Answer

D

Explanation

Substitute the point x=−3,y=−10x = -3, y = -10 into y=2x2+3x−19y = 2x^2 + 3x - 19: y=2(−3)2+3(−3)−19=18−9−19=−10y = 2(-3)^2 + 3(-3) - 19 = 18 - 9 - 19 = -10.

This point satisfies option D. Hence, option D is correct.

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