Number of Negative Integer Solutions

XAT 2019 · Quantitative Ability & Data Interpretation · Medium · Algebra

Consider the function f(x)=(x+4)(x+6)(x+8)⋯(x+98)f(x) = (x + 4)(x + 6)(x + 8) \cdots (x + 98). The number of integers xx for which f(x)<0f(x) < 0 is:

  1. A.

    23

  2. B.

    26

  3. C.

    24

  4. D.

    48

  5. E.

    25

Answer

C

Explanation

The function f(x)f(x) has 48 roots: −4,−6,−8,…,−98-4, -6, -8, \dots, -98. For x>−4x > -4 or x<−98x < -98, all 48 factors have the same sign (all positive or all negative), so f(x)>0f(x) > 0. f(x)<0f(x) < 0 when an odd number of factors are negative. This occurs in intervals between odd roots:

  • (−6,−4)(-6, -4): x=−5x = -5 (1 value)
  • (−10,−8)(-10, -8): x=−9x = -9 (1 value)
  • ...
  • (−98,−96)(-98, -96): x=−97x = -97 (1 value) These form an AP: −5,−9,−13,…,−97-5, -9, -13, \dots, -97. Number of terms =−97−(−5)−4+1=24= \frac{-97 - (-5)}{-4} + 1 = 24.

Related Algebra questions

Practise this under exam conditions

Sign in to solve it with a live timer, the on-screen CAT calculator, and streak and accuracy tracking across every question you attempt.

Solve in the workspace