Question

On the bank of the pristine Tunga river, a deer and a tiger are joyfully playing with each other. The deer notices that it is 40 steps away from the tiger and starts running towards it. At the same time, the tiger starts running away from the deer. Both run on the same straight line. For every five steps the deer takes, the tiger takes six. However, the deer takes only two steps to cover the distance that the tiger covers in three. In how many steps can the deer catch the tiger?

Accepted Answer

A. Let step size of tiger = $t$, step size of deer = $d$. $2d = 3t \implies d = 1.5t$. In unit time, deer takes 5 steps, covers distance = $5d = 5(1.5t) = 7.5t$. In unit time, tiger takes 6 steps, covers distance = $6t$. Relative speed = $7.5t - 6t = 1.5t$ per unit time. Initial distance = 40 deer steps = $40 	imes 1.5t = 60t$. Time to catch = $\frac{60t}{1.5t} = 40$ time units. In 40 time units, deer takes $40 	imes 5 = 200$ steps.

Deer and Tiger Chase Problem

Explanation

Practise this under exam conditions