Encryption System Parameter k

XAT 2021 · Quantitative Ability & Data Interpretation · Medium · Logical Reasoning

An encryption system operates as follows: Step 1. Fix a number kk (k≤26k \le 26). Step 2. For each word, swap the first kk letters from the front with the last kk letters from the end in reverse order. If a word contains less than 2k2k letters, write the entire word in reverse order. Step 3. Replace each letter by a letter kk spaces ahead in the alphabet. If you cross Z in the process to move kk steps ahead, start again from A. Example: k=2k = 2: zebra --> arbez --> ctdgb. If the word "flight" becomes "znmorl" after encryption, then the value of k:

  1. A.

    5

  2. B.

    4

  3. C.

    7

  4. D.

    Cannot be determined uniquely from the given information

  5. E.

    6

Answer

E

Explanation

"flight" has 6 letters. If k=6k = 6, word length ≤2k\le 2k, so step 2 reverses "flight" to "thgilf". Step 3 shifts each letter by 6: 't' + 6 = 'z' 'h' + 6 = 'n' 'g' + 6 = 'm' 'i' + 6 = 'o' 'l' + 6 = 'r' 'f' + 6 = 'l' Result is "znmorl". Thus, k=6k = 6.

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