Encryption System Parameter k
XAT 2021 · Quantitative Ability & Data Interpretation · Medium · Logical Reasoning
An encryption system operates as follows: Step 1. Fix a number (). Step 2. For each word, swap the first letters from the front with the last letters from the end in reverse order. If a word contains less than letters, write the entire word in reverse order. Step 3. Replace each letter by a letter spaces ahead in the alphabet. If you cross Z in the process to move steps ahead, start again from A. Example: : zebra --> arbez --> ctdgb. If the word "flight" becomes "znmorl" after encryption, then the value of k:
- A.
5
- B.
4
- C.
7
- D.
Cannot be determined uniquely from the given information
- E.
6
E
Explanation
"flight" has 6 letters. If , word length , so step 2 reverses "flight" to "thgilf". Step 3 shifts each letter by 6: 't' + 6 = 'z' 'h' + 6 = 'n' 'g' + 6 = 'm' 'i' + 6 = 'o' 'l' + 6 = 'r' 'f' + 6 = 'l' Result is "znmorl". Thus, .
Related Logical Reasoning questions
- #1956Student Rank Order LogicXATDMMCQHard
- #2100Logic Puzzle: Silver Bar Daily RentXATDMMCQMedium
- #2103Raja Harish Chandra Club Friendship GraphXATDMSET · 2QHard
- #2105Logical Reasoning: Rajdhani Express PassengersXATDMSET · 3QHard
- #2106Logical Reasoning: Hostel Room AllocationXATDMSET · 3QHard
- #2120Combinatorics: Football League TournamentXATQADIMCQHard
- #2122Josephus Problem: Circle EliminationXATQADISET · 2QHard
- #2162NWC Financial Scam Logic PuzzleXATDMSET · 2QHard
Practise this under exam conditions
Sign in to solve it with a live timer, the on-screen CAT calculator, and streak and accuracy tracking across every question you attempt.
Solve in the workspace