Data Analyst Applicants Expertise

XAT 2024 · Quantitative Ability & Data Interpretation · Medium · Data Interpretation

Passage / data set

41 applicants have been shortlisted for interviews for some data analyst positions. Some of the applicants have advanced expertise in one or more fields among the following: data analysis, database handling and coding. The numbers of applicants with different advanced expertise are given in the 2×82 \times 8 table below. The number of applicants with advanced expertise in all three fields is given as xx in the table, where xx is a non-negative integer.

FieldData AnalysisDatabase HandlingCodingData Analysis and Database HandlingDatabase Handling and CodingDatabase Analysis and CodingAll three
Number of candidates with Advanced Expertise1257236xx

Question 1 of 2

What BEST can be concluded about the value of xx?

  1. A.

    0, 1 or 2

  2. B.

    2 only

  3. C.

    1 only

  4. D.

    0 or 1 only

  5. E.

    1 or 2 only

Answer

B

Explanation

From the Venn diagram regions:

  • The number of candidates with expertise ONLY in Data Analysis & Database Handling is 2−x≥0  ⟹  x≤22 - x \ge 0 \implies x \le 2.
  • The number of candidates with expertise ONLY in Database Analysis & Coding is 6−x6 - x.
  • The number of candidates with expertise ONLY in Database Handling & Coding is 3−x3 - x.
  • The number of candidates with expertise ONLY in Database Handling is 5−(2−x)−(3−x)−x=x−2≥0  ⟹  x≥25 - (2-x) - (3-x) - x = x - 2 \ge 0 \implies x \ge 2.

Since x≤2x \le 2 and x≥2x \ge 2, xx must be 22 only.

Question 2 of 2

How many applicants DID NOT have advanced expertise in any of the three given fields?

  1. A.

    Cannot be determined uniquely from the given information.

  2. B.

    25

  3. C.

    26

  4. D.

    27

  5. E.

    28

Answer

C

Explanation

With x=2x = 2, the number of applicants in each region of the Venn diagram are:

  • Only Data Analysis: 12−(2−x)−(6−x)−x=12−0−4−2=612 - (2-x) - (6-x) - x = 12 - 0 - 4 - 2 = 6
  • Only Database Handling: x−2=0x - 2 = 0
  • Only Coding: 7−(6−x)−(3−x)−x=7−4−1−2=07 - (6-x) - (3-x) - x = 7 - 4 - 1 - 2 = 0
  • Exactly two fields: (2−x)+(6−x)+(3−x)=0+4+1=5(2-x) + (6-x) + (3-x) = 0 + 4 + 1 = 5
  • All three fields: x=2x = 2

Total applicants with at least one field of expertise =6+0+0+5+2=13+x=15= 6 + 0 + 0 + 5 + 2 = 13 + x = 15. Total shortlisted applicants =41= 41. Applicants without advanced expertise in any of the three fields =41−15=26= 41 - 15 = 26.

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