Brijbhushan's Microfinance Lends

XAT 2026 · Quantitative Ability & Data Interpretation · Hard · Data Interpretation

Passage / data set

Read the following scenario and answer the THREE questions that follow.

Brijbhushan, a microfinancier, lends money at the rate of Rs.10 per square meter to small farmers at a village. He charges an annual interest rate of 10%. All the farming plots in that village are rectangular, with areas varying between a minimum of 1000 square meters and a maximum of 10,000 square meters.

This year, Brijbhushan has lent money only to five farmers: Aditya, Binod, Chhuttan, Dabloo and Govind. The perimeter of Chhuttan's plot is 250 meters, with the length and width being at a ratio of 4:1. Aditya's plot has an area three times the area of Govind's plot. The area of Aditya's plot is also the average of the areas of Govind's plot and Dabloo's plot. The plots belonging to Aditya, Binod and Dabloo are of the same width, but of different lengths. Moreover, the length of Binod's plot is the sum of the lengths of Aditya's plot and Dabloo's plot.

Question 1 of 3

What is the interest owed by Chhuttan to Brijbhushan at the end of the year?

  1. A.

    Rs. 2000

  2. B.

    Rs. 3500

  3. C.

    Rs. 5000

  4. D.

    Rs. 4000

  5. E.

    Rs. 2500

Answer

E

Explanation

Chhuttan's plot perimeter = 2(l+w)=250  ⟹  l+w=1252(l + w) = 250 \implies l + w = 125. Ratio l:w=4:1  ⟹  w=25 m,l=100 ml:w = 4:1 \implies w = 25\text{ m}, l = 100\text{ m}. Area = 100×25=2500 m2100 \times 25 = 2500\text{ m}^2. Loan = 2500×10=Rs. 25,0002500 \times 10 = \text{Rs. } 25,000. Interest at 10% = 10%×25000=Rs. 250010\% \times 25000 = \text{Rs. } 2500.

Question 2 of 3

What is the MAXIMUM possible value of the total loan Brijbhushan has given to these five farmers?

  1. A.

    None of the other options is correct

  2. B.

    Rs. 250,000

  3. C.

    Rs. 237,500

  4. D.

    Rs. 232,500

  5. E.

    Rs. 242,500

Answer

C

Explanation

Let Govind's plot area = xx. Aditya's plot area = 3x3x. Average of Govind's (xx) and Dabloo's (yy) area = 3x  ⟹  x+y2=3x  ⟹  y=5x3x \implies \frac{x+y}{2} = 3x \implies y = 5x. Binod's plot length is sum of Aditya's and Dabloo's length (with same width)   ⟹  \implies Binod's area = 3x+5x=8x3x + 5x = 8x. Total area = x(Govind)+3x(Aditya)+5x(Dabloo)+8x(Binod)+2500(Chhuttan)=17x+2500x (\text{Govind}) + 3x (\text{Aditya}) + 5x (\text{Dabloo}) + 8x (\text{Binod}) + 2500 (\text{Chhuttan}) = 17x + 2500.

Maximum area for any plot is 10,000 m210,000\text{ m}^2. The largest plot is Binod's (8x8x). 8x≤10000  ⟹  x≤12508x \le 10000 \implies x \le 1250. Maximum Total Area = 17(1250)+2500=21250+2500=23750 m217(1250) + 2500 = 21250 + 2500 = 23750\text{ m}^2. Maximum Total Loan = 23750×10=Rs. 237,50023750 \times 10 = \text{Rs. } 237,500.

Question 3 of 3

If the width of the Aditya's plot is 25 meters, what is the MINIMUM possible length of Binod's plot?

  1. A.

    360 meters

  2. B.

    320 meters

  3. C.

    250 meters

  4. D.

    400 meters

  5. E.

    280 meters

Answer

B

Explanation

If width =25 m= 25\text{ m}, then for Binod's plot, Area =8x= 8x, so Length =8x25= \frac{8x}{25}. To minimize Binod's length, we need to minimize xx. Minimum area of any plot is 1000 m21000\text{ m}^2. Govind's plot has area xx, so minimum x=1000x = 1000. Minimum length of Binod's plot =8×100025=320 meters= \frac{8 \times 1000}{25} = 320\text{ meters}.

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