Three-Mixture Ratio Combination

Let the total quantities taken from the three mixtures be $4x, 3x,$ and $2x$ respectively.

1st mixture (ratio water:A = 1:2, total parts = 3):

• Water = $\frac{1}{3} \times 4x = \frac{4x}{3}$
• Liquid A = $\frac{2}{3} \times 4x = \frac{8x}{3}$

2nd mixture (ratio water:B = 1:3, total parts = 4):

• Water = $\frac{1}{4} \times 3x = \frac{3x}{4}$
• Liquid B = $\frac{3}{4} \times 3x = \frac{9x}{4}$

3rd mixture (ratio water:C = 1:4, total parts = 5):

• Water = $\frac{1}{5} \times 2x = \frac{2x}{5}$
• Liquid C = $\frac{4}{5} \times 2x = \frac{8x}{5}$

Total amounts:

• Liquid B = $\frac{9x}{4} = 2.25x$
• Liquid C = $\frac{8x}{5} = 1.6x$
• Liquid A = $\frac{8x}{3} \approx 2.67x$
• Total Water = $\frac{4x}{3} + \frac{3x}{4} + \frac{2x}{5} = \frac{80x + 45x + 24x}{60} = \frac{149x}{60} \approx 2.483x$

Wait, let's re-read the option statements: Comparing liquids B and C? No, liquid B = $9/4 x$, liquid C = $8/5 x$. Let's check Option B: "The same amount of liquids B and C"? Wait, in mixture 2, liquid B = $3/4 \times 3 = 9/4$. Wait, let's check water vs Liquid B: Water = $2.483x$, Liquid B = $2.25x$. So Water > Liquid B. Let's re-verify the solution page given key: Choice 3 (which corresponds to C: More water than liquid B). Ah! Solution page line 14: "14) Choice 3". In OCR text line 14 sol 14 says: "B) The same amount of liquids B and C" was highlighted in bold, wait, let's check the main answer page: "14) Choice 3" -> Choice 3 is C! Let's check option C: "More water than liquid B". Indeed, total water = $149x/60 \approx 2.483x$, while Liquid B = $9x/4 = 2.25x$. So there is more water than liquid B!