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Weight of metal C in alloy

CAT 2020 Slot 1 · Quantitative Ability · Easy · Mixtures

This is an easy Quantitative Ability question from the CAT 2020 Slot 1 paper. It tests Mixtures. The full answer key and a step-by-step explanation are below — try it yourself first, then reveal the solution.

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An alloy is prepared by mixing metals A, B, C in the proportion 3:4:73 : 4 : 7 by volume. Weights of the same volume of metals A, B, C are in the ratio 5:2:65 : 2 : 6. In 130 kg of the alloy, the weight, in kg, of the metal C is

  1. A.

    84

  2. B.

    48

  3. C.

    96

  4. D.

    70

Answer

A

Explanation

Weight ratio of metals A, B, C is given by: Ratio of Weight=(Ratio of Volume)×(Ratio of Density)\text{Ratio of Weight} = (\text{Ratio of Volume}) \times (\text{Ratio of Density}) Weight of A : B : C=(3×5):(4×2):(7×6)=15:8:42\text{Weight of A : B : C} = (3 \times 5) : (4 \times 2) : (7 \times 6) = 15 : 8 : 42

Sum of weight ratio parts =15+8+42=65= 15 + 8 + 42 = 65.

Weight of Metal C in 130 kg alloy: =4265×130=84 kg= \frac{42}{65} \times 130 = 84\text{ kg}

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