Five Consecutive Odd and Even Sequences

CAT 2017 Slot 2 · QA · Medium · Progressions

Let a1,a2,a3,a4,a5a_1, a_2, a_3, a_4, a_5 be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a32a_3. If the sum of the numbers in the new sequence is 450, then a5a_5 is

Answer

51

Explanation

Let the 5 consecutive even numbers ending with 2a32a_3 be: 2a38,2a36,2a34,2a32,2a32a_3 - 8, 2a_3 - 6, 2a_3 - 4, 2a_3 - 2, 2a_3.

Their sum = 10a32010a_3 - 20.

Given sum = 450: 10a320=450    10a3=470    a3=4710a_3 - 20 = 450 \implies 10a_3 = 470 \implies a_3 = 47

Since a1,a2,a3,a4,a5a_1, a_2, a_3, a_4, a_5 are consecutive odd numbers: a5=a3+4=47+4=51a_5 = a_3 + 4 = 47 + 4 = 51.

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