Two Cars Meeting Point

Let $AP = d$, so $BP = 3d$. Let speed of Car 1 = $2v$, speed of Car 2 = $v$. Time taken by Car 1 to reach P: $t_1 = \frac{d}{2v}$. Time taken by Car 2 to reach P: $t_2 = \frac{3d}{v}$. Given $t_2 - t_1 = 1$ hour = 60 minutes. $\frac{3d}{v} - \frac{d}{2v} = 60 \Rightarrow \frac{5d}{2v} = 60 \Rightarrow \frac{d}{2v} = 12$ minutes. So Car 1 takes 12 minutes to reach P from A.