MBApyq

Partha and Narayan Travel Times

CAT 2019 Slot 1 · Quantitative Ability · Easy · Speed, Time and Distance

This is an easy Quantitative Ability question from the CAT 2019 Slot 1 paper. It tests Speed, Time and Distance. The full answer key and a step-by-step explanation are below — try it yourself first, then reveal the solution.

All CAT 2019 Slot 1 questionsMore Speed, Time and Distance questionsAll CAT QA

The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, is

  1. A.

    6

  2. B.

    3

  3. C.

    4

  4. D.

    5

Answer

D

Explanation

Let Partha's time to reach B be TPT_P and Narayan's time be TNT_N. TP=TN+4T_P = T_N + 4. Partha reaches the mid-point (30 km) in time TP2\frac{T_P}{2}. Given TP2=TN−2\frac{T_P}{2} = T_N - 2. TP=2TN−4T_P = 2 T_N - 4. Equating both expressions for TPT_P: TN+4=2TN−4⇒TN=8T_N + 4 = 2 T_N - 4 \Rightarrow T_N = 8 hours. TP=12T_P = 12 hours. Speed of Partha = 60/12=560 / 12 = 5 km/hr.

Related Speed, Time and Distance questions

Practise this under exam conditions

Sign in to solve it with a live timer, the on-screen CAT calculator, and streak and accuracy tracking across every question you attempt.

Solve in the workspace