System of Nested Logarithms

CAT 2019 Slot 1 · QA · Easy · Logarithms

If log2(5+log3a)=3\log_2(5 + \log_3 a) = 3 and log5(4a+12+log2b)=3\log_5(4a + 12 + \log_2 b) = 3, then a+ba + b is equal to:

  1. A.

    32

  2. B.

    59

  3. C.

    67

  4. D.

    40

Answer

B

Explanation

From first equation: 5+log3a=23=8log3a=3a=33=275 + \log_3 a = 2^3 = 8 \Rightarrow \log_3 a = 3 \Rightarrow a = 3^3 = 27.

Substitute a=27a = 27 into second equation: log5(4(27)+12+log2b)=3\log_5(4(27) + 12 + \log_2 b) = 3 log5(108+12+log2b)=3120+log2b=53=125\log_5(108 + 12 + \log_2 b) = 3 \Rightarrow 120 + \log_2 b = 5^3 = 125 log2b=5b=25=32\log_2 b = 5 \Rightarrow b = 2^5 = 32.

a+b=27+32=59a + b = 27 + 32 = 59.

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