Meeting time of two trains

CAT 2020 Slot 3 · QA · Easy · Time speed and Distance

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A and B are two railway stations 90 km90\text{ km} apart. A train leaves A at 9:00 am, heading towards B at a speed of 40 km/hr40\text{ km/hr}. Another train leaves B at 10:30 am, heading towards A at a speed of 20 km/hr20\text{ km/hr}. The trains meet each other at

  1. A.

    11 : 20 am

  2. B.

    11 : 00 am

  3. C.

    10 : 45 am

  4. D.

    11 : 45 am

Answer

B

Explanation

From 9:00 am to 10:30 am (1.5 hours), train from A travels 40×1.5=60 km40 \times 1.5 = 60\text{ km}. Distance remaining between the two trains at 10:30 am = 90−60=30 km90 - 60 = 30\text{ km}.

Relative speed = 40+20=60 km/hr40 + 20 = 60\text{ km/hr}. Time taken to meet after 10:30 am = 3060=0.5 hours=30 minutes\frac{30}{60} = 0.5\text{ hours} = 30\text{ minutes}.

Meeting time = 10:30 am+30 minutes=11:00 am10:30\text{ am} + 30\text{ minutes} = 11:00\text{ am}.

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