Cost Equivalent Baskets of Fruits

Let $a, o, m$ be the costs of an apple, an orange, and a mango respectively. From the given problem: $2a + 4o + 6m = 1a + 4o + 8m = 8o + 7m$

Equating the first two expressions: $2a + 4o + 6m = a + 4o + 8m \implies a = 2m$

Equating the second and third expressions: $a + 4o + 8m = 8o + 7m$ Substitute $a = 2m$: $2m + 4o + 8m = 8o + 7m \implies 10m + 4o = 8o + 7m \implies 3m = 4o \implies o = \frac{3}{4}m$

Now find total cost in terms of $m$: $\text{Total Cost} = 8o + 7m = 8\left(\frac{3}{4}m\right) + 7m = 6m + 7m = 13m$

Thus, a basket of 13 mangoes has the same cost.