Taxi and Bullock Cart Fare Problem

XAT 2013 · Quantitative Ability & Data Interpretation · Medium · Linear Equations

The taxis plying in Wasseypur have the following fare structure: Rs 20 for the first two kilometers, Rs 5 for every km in excess of 2 km and up to 10 km, and Rs 8 for every km in excess of 10 km. Bullock carts on the other hand charge Rs 2 per km. Sardar Khan takes a taxi from the Wasseypur railway station to his home. On the way, at a distance of 14 km from the railway station, he meets Faizal Khan, and gets down from the taxi to talk to him. Later he takes a bullock cart to reach his home. He spends a total of Rs 102 to reach his home from the railway station. How far is his home from the railway station (in kilometers)?

  1. A.

    17

  2. B.

    18

  3. C.

    19

  4. D.

    20

  5. E.

    21

Answer

C

Explanation

Taxi fare for 14 km: First 2 km = Rs 20 Next 8 km (2 to 10 km) = 8×5=408 \times 5 = 40 Next 4 km (10 to 14 km) = 4×8=324 \times 8 = 32 Total taxi fare = 20+40+32=9220 + 40 + 32 = 92. Remaining money spent on bullock cart = 102−92=10102 - 92 = 10. Distance by bullock cart = 10/2=510 / 2 = 5 km. Total distance = 14+5=1914 + 5 = 19 km.

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