Time and Work with Inequality Constraints

CAT 2023 Slot 3 · QA · Hard · Arithmetic

Rahul, Rakshita and Gurmeet, working together, would have taken more than 7 days to finish a job. On the other hand, Rahul and Gurmeet, working together would have taken less than 15 days to finish the job. However, they all worked together for 6 days, followed by Rakshita, who worked alone for 3 more days to finish the job. If Rakshita had worked alone on the job then the number of days she would have taken to finish the job, cannot be

  1. A.

    17

  2. B.

    21

  3. C.

    16

  4. D.

    20

Answer

B

Explanation

Let R,K,GR, K, G be the daily work rates of Rahul, Rakshita, and Gurmeet respectively.

From the actual work done: 6(R+K+G)+3K=1    6(R+G)+9K=16(R + K + G) + 3K = 1 \implies 6(R + G) + 9K = 1 Let TT be the number of days Rakshita takes alone, so K=1/TK = 1/T. Thus, 6(R+G)=19T6(R + G) = 1 - \frac{9}{T}.

Given conditions:

  1. All three together take more than 7 days: 1R+K+G>7    R+K+G<17\frac{1}{R + K + G} > 7 \implies R + K + G < \frac{1}{7} Substitute R+G=16(19K)R + G = \frac{1}{6}\left(1 - 9K\right): 16(19K)+K<17    1612K<17    12K>142    K>121    T<21\frac{1}{6}(1 - 9K) + K < \frac{1}{7} \implies \frac{1}{6} - \frac{1}{2}K < \frac{1}{7} \implies \frac{1}{2}K > \frac{1}{42} \implies K > \frac{1}{21} \implies T < 21

  2. Rahul and Gurmeet together take less than 15 days: 1R+G<15    R+G>115\frac{1}{R + G} < 15 \implies R + G > \frac{1}{15} Substitute R+G=16(19K)R + G = \frac{1}{6}(1 - 9K): 16(19K)>115    19K>25    9K<35    K<115    T>15\frac{1}{6}(1 - 9K) > \frac{1}{15} \implies 1 - 9K > \frac{2}{5} \implies 9K < \frac{3}{5} \implies K < \frac{1}{15} \implies T > 15

Thus, 15<T<2115 < T < 21.

Hence, TT cannot be 2121.

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