Area swept by minute hand

In 30 minutes, the minute hand sweeps a semicircle ($180^\circ$). $\text{Area} = \frac{\pi r^2}{2} = \frac{3.14 \times (42)^2}{2} = 3.14 \times 882 = 2769.48 \approx 2769.5\text{ mm}^2$.