Question

Ramesh works A hours a day and rests B hours a day. This pattern continues for 1 week, with an exactly opposite pattern next week, and so on for four weeks. Every fifth week he adopts a new pattern which then continues for the next four weeks. When he works longer than he rests, his wage per hour is three times what he earns per hour when he rests longer than he works. The following table shows his daily working hours for the week numbered 1 to 13.

Week	1st	5th	9th	13th
Rest	3	4	5
Work	6	8	9	8

A week consists of six days and a month consists of four weeks. If Ramesh is paid Rs. 60 per working hour in the 1st week, what is his salary for the 1st month? (Assume that he is paid half his wages for his resting hours on duty)

Accepted Answer

A. In Week 1: Work = 6, Rest = 3. Work > Rest $\implies$ Working wage = Rs. 60/hr, Resting wage = Rs. 30/hr. Daily pay in Week 1 = $(6 	imes 60) + (3 	imes 30) = 360 + 90 = 450$. Weekly pay = $450 	imes 6 = 2700$. Week 3 has the same pattern as Week 1 $\implies 2700$. In Week 2 (Opposite pattern): Work = 3, Rest = 6. Work < Rest $\implies$ Working wage = Rs. 20/hr, Resting wage = Rs. 10/hr. Daily pay in Week 2 = $(3 	imes 20) + (6 	imes 10) = 60 + 60 = 120$. Weekly pay = $120 	imes 6 = 720$. Week 4 has the same pattern as Week 2 $\implies 720$. Total salary for 1st month = $2700 + 720 + 2700 + 720 = 	ext{Rs. } 6840$.

Ramesh work rest pay pattern

Explanation

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