Permutations of 10-Digit Number

The given number 2435753228 has 10 digits: 5 odd digits (3, 3, 5, 5, 7) and 5 even digits (2, 2, 2, 4, 8). The odd digits must go into the 5 even places, which can be arranged in $\frac{5!}{2! 2!}$ ways. The even digits go into the remaining 5 odd places, which can be arranged in $\frac{5!}{3!}$ ways. Total number of arrangements = $\frac{5!}{2! 2!} \times \frac{5!}{3!} = \frac{(5!)^2}{3!(2!)^2}$.