Question

Find the number of permutations that can be made from the letters of the word OMEGA, if the vowels occupy odd places.

Accepted Answer

A. Word OMEGA has 5 letters: Vowels (O, E, A) - 3; Consonants (M, G) - 2. 5 positions: 1st, 2nd, 3rd, 4th, 5th. Odd positions are 1st, 3rd, 5th (3 positions). Number of ways to arrange 3 vowels in 3 odd positions = $3! = 6$. Number of ways to arrange 2 consonants in 2 remaining even positions (2nd, 4th) = $2! = 2$. Total permutations = $6 	imes 2 = 12$ ways. Hence, Option A is correct.

Permutations of OMEGA

Explanation

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