Question

Given below are two statements:

Statement I : A coin is tossed three times. The probability of getting exactly two heads is 3/8 Statement II: In tossing of 10 coins, the probability of getting exactly 5 heads is 63/256

In the light of the above statements, choose the correct answer from the options given below.

Accepted Answer

A. Statement I: $P(X=2) = \binom{3}{2}\left(\frac{1}{2}ight)^3 = 3 	imes \frac{1}{8} = \frac{3}{8}$. True. Statement II: $P(X=5) = \binom{10}{5}\left(\frac{1}{2}ight)^{10} = \frac{252}{1024} = \frac{63}{256}$. True. Both statements are true.

Coin tossing probability statements

Explanation

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