MBApyq

Probability of Red and Yellow Balls

CMAT 2022 · Quantitative Techniques & Data Interpretation · Easy · Probability

All CMAT 2022 questionsMore Probability questionsAll CMAT QTDI

A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two balls are drawn at random from the bag, one after another, what is the probability that the first ball drawn was red and the second ball drawn was yellow in colour?

  1. A.

    314\frac{3}{14}

  2. B.

    57\frac{5}{7}

  3. C.

    17\frac{1}{7}

  4. D.

    114\frac{1}{14}

Answer

C

Explanation

Total number of balls = 6+11+5=226 + 11 + 5 = 22.

Probability of drawing a red ball first: P(Red1)=622P(\text{Red}_1) = \frac{6}{22}

After drawing one red ball, 21 balls remain in the bag. Probability of drawing a yellow ball second: P(Yellow2∣Red1)=1121P(\text{Yellow}_2 | \text{Red}_1) = \frac{11}{21}

Combined probability: P=622×1121=311×1121=321=17P = \frac{6}{22} \times \frac{11}{21} = \frac{3}{11} \times \frac{11}{21} = \frac{3}{21} = \frac{1}{7}

Related Probability questions

Practise this under exam conditions

Sign in to solve it with a live timer, the on-screen CAT calculator, and streak and accuracy tracking across every question you attempt.

Solve in the workspace