Engineering Specialisations Data Interpretation

Let $C, M, E$ be the number of students in Computer Science, Mechanical, and Electronics respectively. Total students = $C + M + E = 240$. Given $C + E = M \implies M + M = 240 \implies M = 120$ and $C + E = 120$.

In Mechanical ($M = 120$): Girls in $M = 42.5\% \text{ of } 120 = 51$. Boys in $M = 120 - 51 = 69$.

In Computer Science ($C$): Girls in $C = \frac{1}{3} \times (\text{Boys in } M) = \frac{1}{3} \times 69 = 23$.

In Electronics ($E$): Girls in $E = 28$.

Total girls = Girls in $M$ + Girls in $C$ + Girls in $E = 51 + 23 + 28 = 102$.

Hence, Option C is correct.

From the set data: Girls in Mechanical = $51$. Number of students in Electronics ($E$) = $60$ (since $E = C = 60$). Percentage = $\frac{51}{60} \times 100\% = 85\%$.

Hence, Option C is correct.

Boys in Mechanical = $69$. Total students in Electronics = $60$. Percentage difference = $\frac{69 - 60}{60} \times 100\% = \frac{9}{60} \times 100\% = 15\%$.

Hence, Option A is correct.