Product of Three Integers

Since $abc > 0$, either all three are positive, or two are negative and one is positive. Multiply numerator and denominator of $\frac{ab}{c}$ by $c$ to get $\frac{abc}{c^2}$. Since $abc > 0$ and $c^2 > 0$, $\frac{ab}{c} > 0$ must always be true.

Hence, Option B is correct.