Two-digit number properties

Let the two-digit number be $10x + y$ where $x$ is the tens digit and $y$ is the units digit. New number formed = $10(2x) + \frac{y}{2} = 20x + \frac{y}{2}$. Number obtained by interchanging digits = $10y + x$. Given $20x + \frac{y}{2} = 10y + x \implies 19x = \frac{19y}{2} \implies y = 2x$. Therefore, the digit in the units place ($y$) is twice the digit in the tens place ($x$).

Hence, Option D is correct.