Monkey Climbing Pole Time

CMAT 2024 · Logical Reasoning · Medium · Speed, Distance and Time

A monkey climbs 20 feet at the beginning of each hour and rests for a while when he slips back 5 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8:00 AM, at what time will he first touch a flag at 110 feet from the ground?

  1. A.

    2:00 PM

  2. B.

    3:00 PM

  3. C.

    4:00 PM

  4. D.

    2:30 PM

Answer

B

Explanation

Net climb per hour = 20−5=1520 - 5 = 15 feet. In 6 hours (from 8:00 AM to 2:00 PM), net climb = 6×15=906 \times 15 = 90 feet. At the start of the 7th hour (2:00 PM), the monkey climbs 20 feet. Height reached = 90+20=11090 + 20 = 110 feet. He touches the flag at 110 feet right at the beginning of the 7th hour, which is 3:00 PM (after 7 hours of ascent cycle start).

Hence, Option B is correct.

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