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Probability of Choosing Marbles

CMAT 2024 · Quantitative Techniques & Data Interpretation · Easy · Modern Math

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A Glass Jar contains 1 Red, 3 Green, 2 Blue and 4 Yellow marbles. If a single marble is chosen then Match List I with List II :

List IList II
A. Probability of yellow marbleI. 310\frac{3}{10}
B. Probability of green marbleII. 710\frac{7}{10}
C. Probability of either green or yellow marbleIII. 12\frac{1}{2}
D. Probability of either red or yellow marbleIV. 410\frac{4}{10}

Choose the correct answer from the options given below:

  1. A.

    (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

  2. B.

    (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

  3. C.

    (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

  4. D.

    (A)-(IV), (B)-(II), (C)-(III), (D)-(I)

Answer

C

Explanation

Total marbles =1+3+2+4=10= 1 + 3 + 2 + 4 = 10.

  • A: P(Yellow)=410  ⟹  IVP(\text{Yellow}) = \frac{4}{10} \implies \text{IV}
  • B: P(Green)=310  ⟹  IP(\text{Green}) = \frac{3}{10} \implies \text{I}
  • C: P(Green or Yellow)=3+410=710  ⟹  IIP(\text{Green or Yellow}) = \frac{3+4}{10} = \frac{7}{10} \implies \text{II}
  • D: P(Red or Yellow)=1+410=510=12  ⟹  IIIP(\text{Red or Yellow}) = \frac{1+4}{10} = \frac{5}{10} = \frac{1}{2} \implies \text{III}

Matches: (A)-(IV), (B)-(I), (C)-(II), (D)-(III).

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