Comparison of Area and Perimeter

CMAT 2026 · Quantitative Techniques & Data Interpretation · Easy · Geometry

Consider the following figures (I, II and III) and the statements (A, B, C and D) regarding them:

  • Figure (I): Rectangle with length 9 cm and breadth 4 cm.
  • Figure (II): Square with side 6 cm.
  • Figure (III): Right-angled triangle with perpendicular sides 9 cm and 8 cm.

Statements:

  • A. The areas of three figures are different
  • B. The areas of three figures are equal
  • C. The perimeters of three figures are equal
  • D. Perimeters of figures (I) and (II) are equal

Choose the correct answer from the options given below:

  1. A.

    A and C only

  2. B.

    B and D only

  3. C.

    B only

  4. D.

    B and C only

Answer

C

Explanation

Area of (I) = 9×4=36 cm29 \times 4 = 36\text{ cm}^2. Area of (II) = 62=36 cm26^2 = 36\text{ cm}^2. Area of (III) = 12×9×8=36 cm2\frac{1}{2} \times 9 \times 8 = 36\text{ cm}^2. Thus, all three areas are equal (Statement B is correct). Perimeter of (I) = 2(9+4)=26 cm2(9+4) = 26\text{ cm}. Perimeter of (II) = 4×6=24 cm4 \times 6 = 24\text{ cm}. Perimeter of (III) = 9+8+81+64=17+145≈29.04 cm9 + 8 + \sqrt{81+64} = 17 + \sqrt{145} \approx 29.04\text{ cm}. So statement D is false and C is false. Hence, B only is correct.

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