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Volume Absorption by Porous Bricks

XAT 2010 · Quantitative Ability & Data Interpretation · Medium · Quantitative Ability

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A tank internally measuring 150cm×120cm×100cm150\text{cm} \times 120\text{cm} \times 100\text{cm} has 1281600cm31281600\text{cm}^3 water in it. Porous bricks are placed in the water until the tank is full up to its brim. Each brick absorbs one tenth of its volume of water. How many bricks, of 20cm×6cm×4cm20\text{cm} \times 6\text{cm} \times 4\text{cm}, can be put in the tank without spilling over the water?

  1. A.

    1100

  2. B.

    1200

  3. C.

    1150

  4. D.

    1250

  5. E.

    None of the above

Answer

B

Explanation

Tank volume =150×120×100=18,00,000 cm3= 150 \times 120 \times 100 = 18,00,000\text{ cm}^3. Empty space in tank =18,00,000−12,81,600=5,18,400 cm3= 18,00,000 - 12,81,600 = 5,18,400\text{ cm}^3. Volume of one brick =20×6×4=480 cm3= 20 \times 6 \times 4 = 480\text{ cm}^3. Effective volume added per brick to tank =480−0.1(480)=432 cm3= 480 - 0.1(480) = 432\text{ cm}^3. Number of bricks N=5,18,400432=1200N = \frac{5,18,400}{432} = 1200.

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