Geometry: Ladder Sliding

XAT 2011 · Quantitative Ability & Data Interpretation · Medium · Geometry

A 25 ft long ladder is placed against the wall with its base 7 ft from the wall. The base of the ladder is drawn out so that the top comes down by half the distance that the base is drawn out. This distance is in the range:

  1. A.

    (2, 7)

  2. B.

    (5, 8)

  3. C.

    (9, 10)

  4. D.

    (3, 7)

  5. E.

    None of the above.

Answer

E

Explanation

Initial height AB=252−72=24AB = \sqrt{25^2 - 7^2} = 24 ft. Base drawn out by 2x2x, top comes down by xx. New base =7+2x= 7 + 2x, new height =24−x= 24 - x. (24−x)2+(7+2x)2=252  ⟹  576−48x+x2+49+28x+4x2=625  ⟹  5x2−20x=0  ⟹  x=4(24 - x)^2 + (7 + 2x)^2 = 25^2 \implies 576 - 48x + x^2 + 49 + 28x + 4x^2 = 625 \implies 5x^2 - 20x = 0 \implies x = 4. Base drawn out =2x=8= 2x = 8 ft. Since 8 is not strictly inside any of the open intervals (2,7), (5,8), (9,10), or (3,7), the answer is E.

Related Geometry questions

Practise this under exam conditions

Sign in to solve it with a live timer, the on-screen CAT calculator, and streak and accuracy tracking across every question you attempt.

Solve in the workspace