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Chemical Mixture Ratio Calculation

XAT 2015 · Quantitative Ability & Data Interpretation · Hard · Quantitative Ability

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Product M is produced by mixing chemical X and chemical Y in the ratio of 5:45 : 4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1:31 : 3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2:12 : 1. Then the final mixture is prepared by mixing 864864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%50\%, how much water had been added to product M?

  1. A.

    328 units

  2. B.

    368 units

  3. C.

    392 units

  4. D.

    616 units

  5. E.

    None of the above

Answer

B

Explanation

In 864864 units of M:

  • Quantity of X = 59×864=480\frac{5}{9} \times 864 = 480 units.
  • Quantity of Y = 49×864=384\frac{4}{9} \times 864 = 384 units.

Content of raw material B in X = 34×480=360\frac{3}{4} \times 480 = 360 units. Content of raw material B in Y = 23×384=256\frac{2}{3} \times 384 = 256 units. Total B in Product M = 360+256=616360 + 256 = 616 units.

Let WW be the units of water added. Since concentration of B in final mixture is 50%50\%, total final mixture = 2×616=12322 \times 616 = 1232 units. Water added W=1232−864=368W = 1232 - 864 = 368 units.

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