Consecutive Day Sums as Powers of 2

XAT 2018 · Quantitative Ability & Data Interpretation · Hard · Quantitative Aptitude

David has an interesting habit of spending money. He spends exactly £X on the Xth day of a month. For example, he spends exactly £5 on the 5th of any month. On a few days in a year, David noticed that his cumulative spending during the last 'four consecutive days' can be expressed as 2N2^N where N is a natural number. What can be the possible value(s) of N?

  1. A.

    5

  2. B.

    6

  3. C.

    7

  4. D.

    8

  5. E.

    N can have more than one value

Answer

B

Explanation

Sum of 4 consecutive days in same month = d+(d+1)+(d+2)+(d+3)=4d+6d + (d+1) + (d+2) + (d+3) = 4d + 6. Setting 4d+6=2N4d + 6 = 2^N:

  • N=5:4d+6=32  ⟹  4d=26N=5: 4d+6=32 \implies 4d=26 (not integer).
  • N=6:4d+6=64  ⟹  4d=58N=6: 4d+6=64 \implies 4d=58 (not integer, but across two month boundaries: e.g., 30th, 31st, 1st, 2nd gives 30+31+1+2=64=2630+31+1+2 = 64 = 2^6). This occurs in 6 months of a year. Thus N=6N = 6 is uniquely possible.

Related Quantitative Aptitude questions

Practise this under exam conditions

Sign in to solve it with a live timer, the on-screen CAT calculator, and streak and accuracy tracking across every question you attempt.

Solve in the workspace